2p(xp+1)-(p^2+4)x=4

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Solution for 2p(xp+1)-(p^2+4)x=4 equation:


Simplifying
2p(xp + 1) + -1(p2 + 4) * x = 4

Reorder the terms:
2p(1 + px) + -1(p2 + 4) * x = 4
(1 * 2p + px * 2p) + -1(p2 + 4) * x = 4
(2p + 2p2x) + -1(p2 + 4) * x = 4

Reorder the terms:
2p + 2p2x + -1(4 + p2) * x = 4

Reorder the terms for easier multiplication:
2p + 2p2x + -1x(4 + p2) = 4
2p + 2p2x + (4 * -1x + p2 * -1x) = 4

Reorder the terms:
2p + 2p2x + (-1p2x + -4x) = 4
2p + 2p2x + (-1p2x + -4x) = 4

Combine like terms: 2p2x + -1p2x = 1p2x
2p + 1p2x + -4x = 4

Solving
2p + 1p2x + -4x = 4

Solving for variable 'p'.

Reorder the terms:
-4 + 2p + 1p2x + -4x = 4 + -4

Combine like terms: 4 + -4 = 0
-4 + 2p + 1p2x + -4x = 0

The solution to this equation could not be determined.

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